GEOL 1100: Global Physical/Descriptive Oceanography

Paper #3: Swimming Upstream

Choose a western boundary current in the ECCO dataset available as preprocessed netcdf in fox-kemper.com/data (I've regridded to eliminate staggered grids and time-averaged for you). Study its volume transport (via u and v) and return flow (via the Sverdrup relation). Time mean fields are fine, but you might want to check out the full set.

Quantitative aspects: Does the volume budget across a latitude line close? Is the meridional flow at the surface or deep or throughout? Is there a northward heat flux implied by this flow?

That is, consider \int v dz. There are 5 ways to get at it. You should contrast some of these results:

  1. Sum up v delta z from ECCO velocities (Called vvel in 3.73) Note that delta z is not constant in the vertical--look up z_w variable from wvel file to figure out the "bottom edges" of each gridcell.
  2. Sverdrup relation (\int v dz = curl(tau)/(rho beta) should agree in the interior, but not in the WBC
  3. Sea Surface Height Geostrophic relation (\int v dz = g H detan/dx / f), should agree across the region. Here etan is the surface height variable of the model
  4. Geostrophic relation based on pressures at depth (v = d phihyd/dx / f), should agree across the region. Here phiHyd is the hydrostatic potential (=pressure/rho0) anomaly.
  5. Calculate the result for dv/dz from the thermal wind relation, based on the potential density anomaly of the section. f dv/dz = - g/(rho_0) drhoanom/dx (Note: there is a small difference between d/dx of density and potential density called the thermobaric effect. This is neglected in this model.)
Qualititative aspects: How does the flow vary in space or time, what does it do?

Consider a western boundary current, perhaps one you have used. We will use the ECCO dataset, which I will preprocess for you to make it easy at fox-kemper.com/data

Choose one latitude, and make a section of some variables. Here are some questions you might ask:

  1. Confirm that the Sverdrup relation holds for the depth-averaged velocity, away from the western boundary current.
  2. How well do the dv/dz estimates agree?
  3. Take a look at the pressure anomaly field. Can you see the impact of the surface height displacements? What about the interior density variations? Does f v = dp/dx /rho_0 = dphihydid/dx make sense? Do you see a level of equal pressure (i.e., a level where phihyd is constant, so v=0, so level of no motion)?

    Overall Objective: How can you understand aspects of the western boundary current: is it driven by surface height anomalies (eta), or thermal wind (rhoanom), or pressure (phihydid which has both eta and rhoanom effects), or the return flow of Sverdrup? What makes the most sense to you?

    NOTES on rhoanom and phihydid******
    Rhoanom is the *potential* density deviation from the background density (rhoanom=potlrho-rho_0). You can expect flow to generally be directed along surfaces of constant rhoanom. You can also understand the values at any depth as corresponding to one another, i.e., rhoanom=60kg/m^3 at 1000m would be denser if adiabatically rearranged to 500m than a parcel already at 500m with rhoanom=40kg/m^3. You can also expect horizontal gradients of rhoanom to correspond to roughtly to thermal wind dv/dz, except for thermobaric effects which should be small. The units are kg/m^3. Generally, you should expect rhoanom to increase with depth.

    phihydid is the perturbation pressure away from hydrostatic (in class we called it p'), which includes both the effects of surface height elevation and the accumulation with depth due to density by the hydrostatic relation on the perturbation pressure (rho-rho_0). Thus, by looking at phihydid, you don't have to mess with calculating the accumulating pressures. The hydrostatic equation relevant for phihydid is:
    d/dz(phihydid)= - (rho-rho_0) g/(rho_0)
    Thus, while phihydid is proportional to pressure, it has units of m^2/s^2, so multiply by rho_0 to get to Pascals if you like. Perhaps best of all is: phihydid*rho_0/10^4 which is the pressure in decibars, roughly equivalent to sea surface height displacements. Thus, at the surface you expect
    phihydid*rho_0/10^4 \approx eta